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Sign up using Facebook. That’s W dissipated in a SOT device. This current is limited by its internal output resistance since iroml2803 doesn’t seem to be a limiting circuit according to the irlml2830 diagram of the output stage.
So if you just short its output to ground, it will die. Sign up or log in Sign up using Google. My thinking is this should lead to current peaks that easily exceed the driver’s 1A maximum peak current and damage the chip, but the evaluation board demonstrates that this datasgeet not the case, datasbeet am I missing? It’s not current that kills a FET, it’s overheating.
Email Required, but never shown. Post as a guest Name. In fact, the datasheet for the MIC states: As long as that doesn’t cause it to get hotter than its maximum junction temperature, no harm will be done.
MOSFETs like the ones in the MIC’s output stage can handle large current pulses for a short time by simply absorbing the heat generated by the pulse in their thermal mass.
The current might be internally limited. The chip specifies the “typical” LO output current as 1A, not an absolute maximum.
On page 4, bottom right, there’s a graph showing the maximum safe operating area SOA of the device. Unimportant 1 6.
Irlml2803 datasheet pdf
Home Questions Tags Users Unanswered. It won’t be able to deliver 1A or more continuously, however – it can only do that for short pulses. The poly most modern processes use poly gates has some resistance; different Fabs have their own secret sauces.
Owing to the fact that this gate driver features adaptive dead-time and thus monitors the gate of the MOSFET to determine when it has fully turned off, a gate resistor prevents proper sensing of the actual gate.
At t 0 any capacitor will act like a short circuit.
The Apps Engineer likely will not have access to any Fab details. It will survive a pulse of 7A at 20V just fine as long as it’s only 10 microseconds long.
IRLML (IRF) PDF技术资料下载 IRLML 供应信息 IC Datasheet 数据表 (2/9 页)